Outro W15
Revie of the week
You can find the key concepts you studied this week in the following short reviews
10.2 Solve Quadratic Equations by Completing the Square
- Binomial Squares Pattern If a, b are real numbers,
(a+b)2=a2+2ab+b2
(a−b)2=a2−2ab+b2
- Complete a Square
To complete the square ofx2+bx+c:
- Step 1. Identify b, the coefficient of x.
- Step 2. Find
(12b)2, the number to complete the square.
- Step 3. Add the
(12b)2 to
x2+bx.
10.3 Solve Quadratic Equations Using the Quadratic Formula
- Quadratic Formula The solutions to a quadratic equation of the form
ax2+bx+c=0,a≠0 are given by the formula:
\(x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\)
- Solve a Quadratic Equation Using the Quadratic Formula
To solve a quadratic equation using the Quadratic Formula.- Step 1. Write the quadratic formula in standard form. Identify the a, b, c values.
- Step 2. Write the quadratic formula. Then substitute in the values of a, b, c.
- Step 3. Simplify.
- Step 4. Check the solutions.
- Using the Discriminant,
b2−4ac, to Determine the Number of Solutions of a Quadratic Equation
For a quadratic equation of the formax2+bx+c=0,a≠0
- if
b2−4ac>0, the equation has 2 solutions.
- if
b2−4ac=0, the equation has 1 solution.
- if
b2−4ac<0, the equation has no real solutions.
- if
- To identify the most appropriate method to solve a quadratic equation:
- Step 1. Try Factoring first. If the quadratic factors easily this method is very quick.
- Step 2. Try the Square Root Property next. If the equation fits the form
ax2+bx+c=0,a≠0 or
a(x−h)2=k, it can easily be solved by using the Square Root Property.
- Step 3. Use the Quadratic Formula. Any other quadratic equation is best solved by using the Quadratic Formula.
10.4 Solve Applications Modeled by Quadratic Equations
- Area of a Triangle For a triangle with base, b, and height, h, the area, A, is given by the formula:
A=12bh
- Pythagorean Theorem In any right triangle, where a and b are the lengths of the legs, and c is the length of the hypothenuse,
a2+b2=c2
- Projectile motion The height in feet, h, of an object shot upwards into the air with initial velocity,
\(v_0\), after t seconds can be modeled by the formula:
\(h=-16t^2+v_0t\)
10.5 Graphing Quadratic Equations in Two Variables
- The graph of every quadratic equation is a parabola.
- Parabola Orientation For the quadratic equation
y=ax2+bx+c, if
-
- a>0, the parabola opens upward.
- a<0, the parabola opens downward.
- Axis of Symmetry and Vertex of a Parabola For a parabola with equation
y=ax2+bx+c:
- The axis of symmetry of a parabola is the line
x=−12b.
- The vertex is on the axis of symmetry, so its x-coordinate is
−b2a.
- To find the y-coordinate of the vertex we substitute
x=−b2a into the quadratic equation.
- The axis of symmetry of a parabola is the line
- Find the Intercepts of a Parabola To find the intercepts of a parabola with equation
y=ax2+bx+c:
y-intercept x-intercepts
Let x=0and solve for y. Let y=0 and solve for
- To Graph a Quadratic Equation in Two Variables
- Step 1. Write the quadratic equation with y on one side.
- Step 2. Determine whether the parabola opens upward or downward.
- Step 3. Find the axis of symmetry.
- Step 4. Find the vertex.
- Step 5. Find the y-intercept. Find the point symmetric to the y-intercept across the axis of symmetry.
- Step 6. Find the x-intercepts.
- Step 7. Graph the parabola.
- Minimum or Maximum Values of a Quadratic Equation
- The y-coordinate of the vertex of the graph of a quadratic equation is the
- minimum value of the quadratic equation if the parabola opens upward.
- maximum value of the quadratic equation if the parabola opens downward.
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